8b^2+16b-37=-5

Solution for 8b^2+16b-37=-5 equation:

8b^2+16b-37=-5

We move all terms to the left:

8b^2+16b-37-(-5)=0

We add all the numbers together, and all the variables

8b^2+16b-32=0

a = 8; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·8·(-32)
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16\sqrt{5}}{2*8}=\frac{-16-16\sqrt{5}}{16}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16\sqrt{5}}{2*8}=\frac{-16+16\sqrt{5}}{16}
$